10-2(3x-2)=6x+8

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Solution for 10-2(3x-2)=6x+8 equation: 



10-2(3x-2)=6x+8

We move all terms to the left:

10-2(3x-2)-(6x+8)=0

We multiply parentheses

-6x-(6x+8)+4+10=0

We get rid of parentheses

-6x-6x-8+4+10=0

We add all the numbers together, and all the variables

-12x+6=0

We move all terms containing x to the left, all other terms to the right

-12x=-6

x=-6/-12

x=1/2

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