10-2(3x-1)6x+10=0

Solution for 10-2(3x-1)6x+10=0 equation:

10-2(3x-1)6x+10=0

We add all the numbers together, and all the variables

-2(3x-1)6x+20=0

We multiply parentheses

-36x^2+12x+20=0

a = -36; b = 12; c = +20;
Δ = b2-4ac
Δ = 122-4·(-36)·20
Δ = 3024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3024}=\sqrt{144*21}=\sqrt{144}*\sqrt{21}=12\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12\sqrt{21}}{2*-36}=\frac{-12-12\sqrt{21}}{-72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12\sqrt{21}}{2*-36}=\frac{-12+12\sqrt{21}}{-72}
$