10-(m+3)=2(m+5)

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Solution for 10-(m+3)=2(m+5) equation: 



10-(m+3)=2(m+5)

We move all terms to the left:

10-(m+3)-(2(m+5))=0

We get rid of parentheses

-m-(2(m+5))-3+10=0



We calculate terms in parentheses: -(2(m+5)), so:

2(m+5)

We multiply parentheses

2m+10

Back to the equation:

-(2m+10)



We add all the numbers together, and all the variables

-1m-(2m+10)+7=0

We get rid of parentheses

-1m-2m-10+7=0

We add all the numbers together, and all the variables

-3m-3=0

We move all terms containing m to the left, all other terms to the right

-3m=3

m=3/-3

m=-1

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