10-(5x+5)+10x=20+(2x+5)

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Solution for 10-(5x+5)+10x=20+(2x+5) equation:



10-(5x+5)+10x=20+(2x+5)
We move all terms to the left:
10-(5x+5)+10x-(20+(2x+5))=0
We add all the numbers together, and all the variables
10x-(5x+5)-(20+(2x+5))+10=0
We get rid of parentheses
10x-5x-(20+(2x+5))-5+10=0
We calculate terms in parentheses: -(20+(2x+5)), so:
20+(2x+5)
determiningTheFunctionDomain (2x+5)+20
We get rid of parentheses
2x+5+20
We add all the numbers together, and all the variables
2x+25
Back to the equation:
-(2x+25)
We add all the numbers together, and all the variables
5x-(2x+25)+5=0
We get rid of parentheses
5x-2x-25+5=0
We add all the numbers together, and all the variables
3x-20=0
We move all terms containing x to the left, all other terms to the right
3x=20
x=20/3
x=6+2/3

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