10-(5-3*a)=+6-2*a-(7+3*a)

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Solution for 10-(5-3*a)=+6-2*a-(7+3*a) equation: 



10-(5-3a)=+6-2a-(7+3a)

We move all terms to the left:

10-(5-3a)-(+6-2a-(7+3a))=0

We add all the numbers together, and all the variables

-(-3a+5)-(+6-2a-(3a+7))+10=0

We get rid of parentheses

3a-(+6-2a-(3a+7))-5+10=0



We calculate terms in parentheses: -(+6-2a-(3a+7)), so:

+6-2a-(3a+7)

determiningTheFunctionDomain
-2a-(3a+7)+6

We get rid of parentheses

-2a-3a-7+6

We add all the numbers together, and all the variables

-5a-1

Back to the equation:

-(-5a-1)



We add all the numbers together, and all the variables

3a-(-5a-1)+5=0

We get rid of parentheses

3a+5a+1+5=0

We add all the numbers together, and all the variables

8a+6=0

We move all terms containing a to the left, all other terms to the right

8a=-6

a=-6/8

a=-3/4

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