10+x=5(1/2)x+2)

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Solution for 10+x=5(1/2)x+2) equation: 



10+x=5(1/2)x+2)

We move all terms to the left:

10+x-(5(1/2)x+2))=0



Domain of the equation: 2)x+2))+10!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

x-(5(+1/2)x+2))+10=0

We multiply all the terms by the denominator


x*2)x+2))+10-(5(+1=0

Wy multiply elements

2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$

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