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10+x=4(1/4x+2)
We move all terms to the left:
10+x-(4(1/4x+2))=0
Domain of the equation: 4x+2))!=0We multiply all the terms by the denominator
x∈R
x*4x+10*4x+2))-(4(1+2))=0
We add all the numbers together, and all the variables
x*4x+10*4x+2))-(43)=0
We add all the numbers together, and all the variables
x*4x+10*4x=0
Wy multiply elements
4x^2+40x=0
a = 4; b = 40; c = 0;
Δ = b2-4ac
Δ = 402-4·4·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-40}{2*4}=\frac{-80}{8} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+40}{2*4}=\frac{0}{8} =0 $
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