10+n+4=2n+3+3(2n-1)

Solution for 10+n+4=2n+3+3(2n-1) equation:

10+n+4=2n+3+3(2n-1)

We move all terms to the left:

10+n+4-(2n+3+3(2n-1))=0

We add all the numbers together, and all the variables

n-(2n+3+3(2n-1))+14=0


We calculate terms in parentheses: -(2n+3+3(2n-1)), so:

2n+3+3(2n-1)

determiningTheFunctionDomain
2n+3(2n-1)+3

We multiply parentheses

2n+6n-3+3

We add all the numbers together, and all the variables

8n

Back to the equation:

-(8n)


We add all the numbers together, and all the variables

-7n+14=0

We move all terms containing n to the left, all other terms to the right

-7n=-14

n=-14/-7

n=+2