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10+5r=1/5(2+r)
We move all terms to the left:
10+5r-(1/5(2+r))=0
Domain of the equation: 5(2+r))!=0We add all the numbers together, and all the variables
r∈R
5r-(1/5(r+2))+10=0
We multiply all the terms by the denominator
5r*5(r+2))-(1+10*5(r+2))=0
Wy multiply elements
25r^2(r+50r(r=0
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