10+5=50x2

Solution for 10+5=50x2 equation:

10+5=50x^2

We move all terms to the left:

10+5-(50x^2)=0

We add all the numbers together, and all the variables

-50x^2+15=0

a = -50; b = 0; c = +15;
Δ = b2-4ac
Δ = 02-4·(-50)·15
Δ = 3000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3000}=\sqrt{100*30}=\sqrt{100}*\sqrt{30}=10\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{30}}{2*-50}=\frac{0-10\sqrt{30}}{-100}
=-\frac{10\sqrt{30}}{-100}
=-\frac{\sqrt{30}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{30}}{2*-50}=\frac{0+10\sqrt{30}}{-100}
=\frac{10\sqrt{30}}{-100}
=\frac{\sqrt{30}}{-10}
$