10+5(z2)=4z+1

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Solution for 10+5(z2)=4z+1 equation: 



10+5(z2)=4z+1

We move all terms to the left:

10+5(z2)-(4z+1)=0

We add all the numbers together, and all the variables

5z^2-(4z+1)+10=0

We get rid of parentheses

5z^2-4z-1+10=0

We add all the numbers together, and all the variables

5z^2-4z+9=0

a = 5; b = -4; c = +9;
Δ = b2-4ac
Δ = -42-4·5·9
Δ = -164
Delta is less than zero, so there is no solution for the equation

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