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10+4y=2(2y+5)
We move all terms to the left:
10+4y-(2(2y+5))=0
We calculate terms in parentheses: -(2(2y+5)), so:We get rid of parentheses
2(2y+5)
We multiply parentheses
4y+10
Back to the equation:
-(4y+10)
4y-4y-10+10=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0
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