10+3(x-4)+3x=12-3(2x-4)-2

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Solution for 10+3(x-4)+3x=12-3(2x-4)-2 equation: 



10+3(x-4)+3x=12-3(2x-4)-2

We move all terms to the left:

10+3(x-4)+3x-(12-3(2x-4)-2)=0

We add all the numbers together, and all the variables

3x+3(x-4)-(12-3(2x-4)-2)+10=0

We multiply parentheses

3x+3x-(12-3(2x-4)-2)-12+10=0



We calculate terms in parentheses: -(12-3(2x-4)-2), so:

12-3(2x-4)-2

determiningTheFunctionDomain
-3(2x-4)+12-2

We add all the numbers together, and all the variables

-3(2x-4)+10

We multiply parentheses

-6x+12+10

We add all the numbers together, and all the variables

-6x+22

Back to the equation:

-(-6x+22)



We add all the numbers together, and all the variables

6x-(-6x+22)-2=0

We get rid of parentheses

6x+6x-22-2=0

We add all the numbers together, and all the variables

12x-24=0

We move all terms containing x to the left, all other terms to the right

12x=24

x=24/12

x=2

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