10+3(r-7)=16-(r+2)

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Solution for 10+3(r-7)=16-(r+2) equation: 


Simplifying
10 + 3(r + -7) = 16 + -1(r + 2)

Reorder the terms:
10 + 3(-7 + r) = 16 + -1(r + 2)
10 + (-7 * 3 + r * 3) = 16 + -1(r + 2)
10 + (-21 + 3r) = 16 + -1(r + 2)

Combine like terms: 10 + -21 = -11
-11 + 3r = 16 + -1(r + 2)

Reorder the terms:
-11 + 3r = 16 + -1(2 + r)
-11 + 3r = 16 + (2 * -1 + r * -1)
-11 + 3r = 16 + (-2 + -1r)

Combine like terms: 16 + -2 = 14
-11 + 3r = 14 + -1r

Solving
-11 + 3r = 14 + -1r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add 'r' to each side of the equation.
-11 + 3r + r = 14 + -1r + r

Combine like terms: 3r + r = 4r
-11 + 4r = 14 + -1r + r

Combine like terms: -1r + r = 0
-11 + 4r = 14 + 0
-11 + 4r = 14

Add '11' to each side of the equation.
-11 + 11 + 4r = 14 + 11

Combine like terms: -11 + 11 = 0
0 + 4r = 14 + 11
4r = 14 + 11

Combine like terms: 14 + 11 = 25
4r = 25

Divide each side by '4'.
r = 6.25

Simplifying
r = 6.25

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