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10+2/3(3-7x)=1/3x+3
We move all terms to the left:
10+2/3(3-7x)-(1/3x+3)=0
Domain of the equation: 3(3-7x)!=0
x∈R
Domain of the equation: 3x+3)!=0We add all the numbers together, and all the variables
x∈R
2/3(-7x+3)-(1/3x+3)+10=0
We get rid of parentheses
2/3(-7x+3)-1/3x-3+10=0
We calculate fractions
6x/(-63x^2+27x)+(-3x(-)/(-63x^2+27x)-3+10=0
We add all the numbers together, and all the variables
6x/(-63x^2+27x)+(-3x0/(-63x^2+27x)-3+10=0
We calculate fractions
We do not support expression: x^3
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