10+16(x-10)=5(x-4)+(x-5)

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Solution for 10+16(x-10)=5(x-4)+(x-5) equation: 



10+16(x-10)=5(x-4)+(x-5)

We move all terms to the left:

10+16(x-10)-(5(x-4)+(x-5))=0

We multiply parentheses

16x-(5(x-4)+(x-5))-160+10=0



We calculate terms in parentheses: -(5(x-4)+(x-5)), so:

5(x-4)+(x-5)

We multiply parentheses

5x+(x-5)-20

We get rid of parentheses

5x+x-5-20

We add all the numbers together, and all the variables

6x-25

Back to the equation:

-(6x-25)



We add all the numbers together, and all the variables

16x-(6x-25)-150=0

We get rid of parentheses

16x-6x+25-150=0

We add all the numbers together, and all the variables

10x-125=0

We move all terms containing x to the left, all other terms to the right

10x=125

x=125/10

x=12+1/2

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