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10+12y=3(3+4y)
We move all terms to the left:
10+12y-(3(3+4y))=0
We add all the numbers together, and all the variables
12y-(3(4y+3))+10=0
We calculate terms in parentheses: -(3(4y+3)), so:We get rid of parentheses
3(4y+3)
We multiply parentheses
12y+9
Back to the equation:
-(12y+9)
12y-12y-9+10=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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