10+10(4x-10)=50-20(2x-5)

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Solution for 10+10(4x-10)=50-20(2x-5) equation: 



10+10(4x-10)=50-20(2x-5)

We move all terms to the left:

10+10(4x-10)-(50-20(2x-5))=0

We multiply parentheses

40x-(50-20(2x-5))-100+10=0



We calculate terms in parentheses: -(50-20(2x-5)), so:

50-20(2x-5)

determiningTheFunctionDomain
-20(2x-5)+50

We multiply parentheses

-40x+100+50

We add all the numbers together, and all the variables

-40x+150

Back to the equation:

-(-40x+150)



We add all the numbers together, and all the variables

40x-(-40x+150)-90=0

We get rid of parentheses

40x+40x-150-90=0

We add all the numbers together, and all the variables

80x-240=0

We move all terms containing x to the left, all other terms to the right

80x=240

x=240/80

x=3

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