10*(x+1)+2x-2=11x+7+2*(x-1)

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Solution for 10*(x+1)+2x-2=11x+7+2*(x-1) equation: 



10(x+1)+2x-2=11x+7+2(x-1)

We move all terms to the left:

10(x+1)+2x-2-(11x+7+2(x-1))=0

We add all the numbers together, and all the variables

2x+10(x+1)-(11x+7+2(x-1))-2=0

We multiply parentheses

2x+10x-(11x+7+2(x-1))+10-2=0



We calculate terms in parentheses: -(11x+7+2(x-1)), so:

11x+7+2(x-1)

determiningTheFunctionDomain
11x+2(x-1)+7

We multiply parentheses

11x+2x-2+7

We add all the numbers together, and all the variables

13x+5

Back to the equation:

-(13x+5)



We add all the numbers together, and all the variables

12x-(13x+5)+8=0

We get rid of parentheses

12x-13x-5+8=0

We add all the numbers together, and all the variables

-1x+3=0

We move all terms containing x to the left, all other terms to the right

-x=-3

x=-3/-1

x=+3

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