10*(3*k+3)=2*(9*k+11)

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Solution for 10*(3*k+3)=2*(9*k+11) equation: 



10(3k+3)=2(9k+11)

We move all terms to the left:

10(3k+3)-(2(9k+11))=0

We multiply parentheses

30k-(2(9k+11))+30=0



We calculate terms in parentheses: -(2(9k+11)), so:

2(9k+11)

We multiply parentheses

18k+22

Back to the equation:

-(18k+22)



We get rid of parentheses

30k-18k-22+30=0

We add all the numbers together, and all the variables

12k+8=0

We move all terms containing k to the left, all other terms to the right

12k=-8

k=-8/12

k=-2/3

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