10(z-1)-21=3(z+7)+4

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Solution for 10(z-1)-21=3(z+7)+4 equation: 



10(z-1)-21=3(z+7)+4

We move all terms to the left:

10(z-1)-21-(3(z+7)+4)=0

We multiply parentheses

10z-(3(z+7)+4)-10-21=0



We calculate terms in parentheses: -(3(z+7)+4), so:

3(z+7)+4

We multiply parentheses

3z+21+4

We add all the numbers together, and all the variables

3z+25

Back to the equation:

-(3z+25)



We add all the numbers together, and all the variables

10z-(3z+25)-31=0

We get rid of parentheses

10z-3z-25-31=0

We add all the numbers together, and all the variables

7z-56=0

We move all terms containing z to the left, all other terms to the right

7z=56

z=56/7

z=8

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