10(z+4)-3(z-1)=3(z-2)+3(z-2)

Solution for 10(z+4)-3(z-1)=3(z-2)+3(z-2) equation:

10(z+4)-3(z-1)=3(z-2)+3(z-2)

We simplify the equation to the form, which is simple to understand 
10(z+4)-3(z-1)=3(z-2)+3(z-2)

Reorder the terms in parentheses
+(+10z+40)-3*(z-1)=3*(z-2)+3*(z-2)

Remove unnecessary parentheses
+10z+40-3+*(+z-1+)=+3+*(+z-2+)+3+*(+z-2+)

Reorder the terms in parentheses
+10z+40+(-3z+3)=3*(z-2)+3*(z-2)

Remove unnecessary parentheses
+10z+40-3z+3=+3+*(+z-2+)+3+*(+z-2+)

Reorder the terms in parentheses
+10z+40-3z+3=+(+3z-6)+3*(z-2)

Remove unnecessary parentheses
+10z+40-3z+3=+3z-6+3+*(+z-2+)

Reorder the terms in parentheses
+10z+40-3z+3=+3z-6+(+3z-6)

Remove unnecessary parentheses
+10z+40-3z+3=+3z-6+3z-6

We move all terms containing z to the left and all other terms to the right. 
+10z-3z-3z-3z=-6-6-40-3

We simplify left and right side of the equation. 
+1z=-55

We divide both sides of the equation by 1 to get z. 
z=-55