10(z+1)-2(z-2)=5(z-1)+2(z-2)

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Solution for 10(z+1)-2(z-2)=5(z-1)+2(z-2) equation: 



10(z+1)-2(z-2)=5(z-1)+2(z-2)

We move all terms to the left:

10(z+1)-2(z-2)-(5(z-1)+2(z-2))=0

We multiply parentheses

10z-2z-(5(z-1)+2(z-2))+10+4=0



We calculate terms in parentheses: -(5(z-1)+2(z-2)), so:

5(z-1)+2(z-2)

We multiply parentheses

5z+2z-5-4

We add all the numbers together, and all the variables

7z-9

Back to the equation:

-(7z-9)



We add all the numbers together, and all the variables

8z-(7z-9)+14=0

We get rid of parentheses

8z-7z+9+14=0

We add all the numbers together, and all the variables

z+23=0

We move all terms containing z to the left, all other terms to the right

z=-23

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