10(y+2)=3(y+5)

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Solution for 10(y+2)=3(y+5) equation: 



10(y+2)=3(y+5)

We move all terms to the left:

10(y+2)-(3(y+5))=0

We multiply parentheses

10y-(3(y+5))+20=0



We calculate terms in parentheses: -(3(y+5)), so:

3(y+5)

We multiply parentheses

3y+15

Back to the equation:

-(3y+15)



We get rid of parentheses

10y-3y-15+20=0

We add all the numbers together, and all the variables

7y+5=0

We move all terms containing y to the left, all other terms to the right

7y=-5

y=-5/7

y=-5/7

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