10(y+2)-y=2(8y-8)

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Solution for 10(y+2)-y=2(8y-8) equation: 



10(y+2)-y=2(8y-8)

We move all terms to the left:

10(y+2)-y-(2(8y-8))=0

We add all the numbers together, and all the variables

-1y+10(y+2)-(2(8y-8))=0

We multiply parentheses

-1y+10y-(2(8y-8))+20=0



We calculate terms in parentheses: -(2(8y-8)), so:

2(8y-8)

We multiply parentheses

16y-16

Back to the equation:

-(16y-16)



We add all the numbers together, and all the variables

9y-(16y-16)+20=0

We get rid of parentheses

9y-16y+16+20=0

We add all the numbers together, and all the variables

-7y+36=0

We move all terms containing y to the left, all other terms to the right

-7y=-36

y=-36/-7

y=5+1/7

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