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10(x-4)=4(2x-1)+5
We move all terms to the left:
10(x-4)-(4(2x-1)+5)=0
We multiply parentheses
10x-(4(2x-1)+5)-40=0
We calculate terms in parentheses: -(4(2x-1)+5), so:We get rid of parentheses
4(2x-1)+5
We multiply parentheses
8x-4+5
We add all the numbers together, and all the variables
8x+1
Back to the equation:
-(8x+1)
10x-8x-1-40=0
We add all the numbers together, and all the variables
2x-41=0
We move all terms containing x to the left, all other terms to the right
2x=41
x=41/2
x=20+1/2
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