10(x-3)x=11x+25

Solution for 10(x-3)x=11x+25 equation:

10(x-3)x=11x+25

We move all terms to the left:

10(x-3)x-(11x+25)=0

We multiply parentheses

10x^2-30x-(11x+25)=0

We get rid of parentheses

10x^2-30x-11x-25=0

We add all the numbers together, and all the variables

10x^2-41x-25=0

a = 10; b = -41; c = -25;
Δ = b2-4ac
Δ = -412-4·10·(-25)
Δ = 2681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-\sqrt{2681}}{2*10}=\frac{41-\sqrt{2681}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+\sqrt{2681}}{2*10}=\frac{41+\sqrt{2681}}{20}
$