10(x-3)=2(x+10)-2

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Solution for 10(x-3)=2(x+10)-2 equation: 



10(x-3)=2(x+10)-2

We move all terms to the left:

10(x-3)-(2(x+10)-2)=0

We multiply parentheses

10x-(2(x+10)-2)-30=0



We calculate terms in parentheses: -(2(x+10)-2), so:

2(x+10)-2

We multiply parentheses

2x+20-2

We add all the numbers together, and all the variables

2x+18

Back to the equation:

-(2x+18)



We get rid of parentheses

10x-2x-18-30=0

We add all the numbers together, and all the variables

8x-48=0

We move all terms containing x to the left, all other terms to the right

8x=48

x=48/8

x=6

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