10(x-2)=9(x-3)+1

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Solution for 10(x-2)=9(x-3)+1 equation: 



10(x-2)=9(x-3)+1

We move all terms to the left:

10(x-2)-(9(x-3)+1)=0

We multiply parentheses

10x-(9(x-3)+1)-20=0



We calculate terms in parentheses: -(9(x-3)+1), so:

9(x-3)+1

We multiply parentheses

9x-27+1

We add all the numbers together, and all the variables

9x-26

Back to the equation:

-(9x-26)



We get rid of parentheses

10x-9x+26-20=0

We add all the numbers together, and all the variables

x+6=0

We move all terms containing x to the left, all other terms to the right

x=-6

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