10(x-2)-3=5-(1-x)

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Solution for 10(x-2)-3=5-(1-x) equation: 



10(x-2)-3=5-(1-x)

We move all terms to the left:

10(x-2)-3-(5-(1-x))=0

We add all the numbers together, and all the variables

10(x-2)-(5-(-1x+1))-3=0

We multiply parentheses

10x-(5-(-1x+1))-20-3=0



We calculate terms in parentheses: -(5-(-1x+1)), so:

5-(-1x+1)

determiningTheFunctionDomain
-(-1x+1)+5

We get rid of parentheses

1x-1+5

We add all the numbers together, and all the variables

x+4

Back to the equation:

-(x+4)



We add all the numbers together, and all the variables

10x-(x+4)-23=0

We get rid of parentheses

10x-x-4-23=0

We add all the numbers together, and all the variables

9x-27=0

We move all terms containing x to the left, all other terms to the right

9x=27

x=27/9

x=3

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