10(x-2)+3(1-x)=9x+2(4-3x)

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Solution for 10(x-2)+3(1-x)=9x+2(4-3x) equation: 



10(x-2)+3(1-x)=9x+2(4-3x)

We move all terms to the left:

10(x-2)+3(1-x)-(9x+2(4-3x))=0

We add all the numbers together, and all the variables

10(x-2)+3(-1x+1)-(9x+2(-3x+4))=0

We multiply parentheses

10x-3x-(9x+2(-3x+4))-20+3=0



We calculate terms in parentheses: -(9x+2(-3x+4)), so:

9x+2(-3x+4)

We multiply parentheses

9x-6x+8

We add all the numbers together, and all the variables

3x+8

Back to the equation:

-(3x+8)



We add all the numbers together, and all the variables

7x-(3x+8)-17=0

We get rid of parentheses

7x-3x-8-17=0

We add all the numbers together, and all the variables

4x-25=0

We move all terms containing x to the left, all other terms to the right

4x=25

x=25/4

x=6+1/4

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