10(x+4)-3(x+1)=-3+8x+34

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Solution for 10(x+4)-3(x+1)=-3+8x+34 equation: 



10(x+4)-3(x+1)=-3+8x+34

We move all terms to the left:

10(x+4)-3(x+1)-(-3+8x+34)=0

We add all the numbers together, and all the variables

10(x+4)-3(x+1)-(8x+31)=0

We multiply parentheses

10x-3x-(8x+31)+40-3=0

We get rid of parentheses

10x-3x-8x-31+40-3=0

We add all the numbers together, and all the variables

-1x+6=0

We move all terms containing x to the left, all other terms to the right

-x=-6

x=-6/-1

x=+6

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