10(x+3)=5(x-4)-12

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Solution for 10(x+3)=5(x-4)-12 equation: 



10(x+3)=5(x-4)-12

We move all terms to the left:

10(x+3)-(5(x-4)-12)=0

We multiply parentheses

10x-(5(x-4)-12)+30=0



We calculate terms in parentheses: -(5(x-4)-12), so:

5(x-4)-12

We multiply parentheses

5x-20-12

We add all the numbers together, and all the variables

5x-32

Back to the equation:

-(5x-32)



We get rid of parentheses

10x-5x+32+30=0

We add all the numbers together, and all the variables

5x+62=0

We move all terms containing x to the left, all other terms to the right

5x=-62

x=-62/5

x=-12+2/5

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