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10(x+3)=3(2x+2)
We move all terms to the left:
10(x+3)-(3(2x+2))=0
We multiply parentheses
10x-(3(2x+2))+30=0
We calculate terms in parentheses: -(3(2x+2)), so:We get rid of parentheses
3(2x+2)
We multiply parentheses
6x+6
Back to the equation:
-(6x+6)
10x-6x-6+30=0
We add all the numbers together, and all the variables
4x+24=0
We move all terms containing x to the left, all other terms to the right
4x=-24
x=-24/4
x=-6
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