10(x+3)=(-9x-4)+x-5+3

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Solution for 10(x+3)=(-9x-4)+x-5+3 equation: 



10(x+3)=(-9x-4)+x-5+3

We move all terms to the left:

10(x+3)-((-9x-4)+x-5+3)=0

We multiply parentheses

10x-((-9x-4)+x-5+3)+30=0



We calculate terms in parentheses: -((-9x-4)+x-5+3), so:

(-9x-4)+x-5+3

We add all the numbers together, and all the variables

x+(-9x-4)-2

We get rid of parentheses

x-9x-4-2

We add all the numbers together, and all the variables

-8x-6

Back to the equation:

-(-8x-6)



We get rid of parentheses

10x+8x+6+30=0

We add all the numbers together, and all the variables

18x+36=0

We move all terms containing x to the left, all other terms to the right

18x=-36

x=-36/18

x=-2

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