10(x+3)-4(x-2)=7

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Solution for 10(x+3)-4(x-2)=7 equation: 



10(x+3)-4(x-2)=7

We move all terms to the left:

10(x+3)-4(x-2)-(7)=0

We multiply parentheses

10x-4x+30+8-7=0

We add all the numbers together, and all the variables

6x+31=0

We move all terms containing x to the left, all other terms to the right

6x=-31

x=-31/6

x=-5+1/6

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