10(x+2)=9(x-3)+x

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Solution for 10(x+2)=9(x-3)+x equation: 



10(x+2)=9(x-3)+x

We move all terms to the left:

10(x+2)-(9(x-3)+x)=0

We multiply parentheses

10x-(9(x-3)+x)+20=0



We calculate terms in parentheses: -(9(x-3)+x), so:

9(x-3)+x

We add all the numbers together, and all the variables

x+9(x-3)

We multiply parentheses

x+9x-27

We add all the numbers together, and all the variables

10x-27

Back to the equation:

-(10x-27)



We get rid of parentheses

10x-10x+27+20=0

We add all the numbers together, and all the variables

47!=0

There is no solution for this equation

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