10(x+2)=9(x+3)+-16

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Solution for 10(x+2)=9(x+3)+-16 equation: 



10(x+2)=9(x+3)+-16

We move all terms to the left:

10(x+2)-(9(x+3)+-16)=0

We use the square of the difference formula

10(x+2)-(9(x+3)-16)=0

We multiply parentheses

10x-(9(x+3)-16)+20=0



We calculate terms in parentheses: -(9(x+3)-16), so:

9(x+3)-16

We multiply parentheses

9x+27-16

We add all the numbers together, and all the variables

9x+11

Back to the equation:

-(9x+11)



We get rid of parentheses

10x-9x-11+20=0

We add all the numbers together, and all the variables

x+9=0

We move all terms containing x to the left, all other terms to the right

x=-9

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