10(x+1)=5(2x-2)

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Solution for 10(x+1)=5(2x-2) equation: 



10(x+1)=5(2x-2)

We move all terms to the left:

10(x+1)-(5(2x-2))=0

We multiply parentheses

10x-(5(2x-2))+10=0



We calculate terms in parentheses: -(5(2x-2)), so:

5(2x-2)

We multiply parentheses

10x-10

Back to the equation:

-(10x-10)



We get rid of parentheses

10x-10x+10+10=0

We add all the numbers together, and all the variables

20!=0

There is no solution for this equation

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