10(x+1)3x=13x+10

Solution for 10(x+1)3x=13x+10 equation:

10(x+1)3x=13x+10

We move all terms to the left:

10(x+1)3x-(13x+10)=0

We multiply parentheses

30x^2+30x-(13x+10)=0

We get rid of parentheses

30x^2+30x-13x-10=0

We add all the numbers together, and all the variables

30x^2+17x-10=0

a = 30; b = 17; c = -10;
Δ = b2-4ac
Δ = 172-4·30·(-10)
Δ = 1489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{1489}}{2*30}=\frac{-17-\sqrt{1489}}{60}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{1489}}{2*30}=\frac{-17+\sqrt{1489}}{60}
$