10(v+2)-4v=3(2v+3)-12

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Solution for 10(v+2)-4v=3(2v+3)-12 equation: 


Simplifying
10(v + 2) + -4v = 3(2v + 3) + -12

Reorder the terms:
10(2 + v) + -4v = 3(2v + 3) + -12
(2 * 10 + v * 10) + -4v = 3(2v + 3) + -12
(20 + 10v) + -4v = 3(2v + 3) + -12

Combine like terms: 10v + -4v = 6v
20 + 6v = 3(2v + 3) + -12

Reorder the terms:
20 + 6v = 3(3 + 2v) + -12
20 + 6v = (3 * 3 + 2v * 3) + -12
20 + 6v = (9 + 6v) + -12

Reorder the terms:
20 + 6v = 9 + -12 + 6v

Combine like terms: 9 + -12 = -3
20 + 6v = -3 + 6v

Add '-6v' to each side of the equation.
20 + 6v + -6v = -3 + 6v + -6v

Combine like terms: 6v + -6v = 0
20 + 0 = -3 + 6v + -6v
20 = -3 + 6v + -6v

Combine like terms: 6v + -6v = 0
20 = -3 + 0
20 = -3

Solving
20 = -3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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