10(v+2)-2v=2(4v+4)-12

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Solution for 10(v+2)-2v=2(4v+4)-12 equation: 



10(v+2)-2v=2(4v+4)-12

We move all terms to the left:

10(v+2)-2v-(2(4v+4)-12)=0

We add all the numbers together, and all the variables

-2v+10(v+2)-(2(4v+4)-12)=0

We multiply parentheses

-2v+10v-(2(4v+4)-12)+20=0



We calculate terms in parentheses: -(2(4v+4)-12), so:

2(4v+4)-12

We multiply parentheses

8v+8-12

We add all the numbers together, and all the variables

8v-4

Back to the equation:

-(8v-4)



We add all the numbers together, and all the variables

8v-(8v-4)+20=0

We get rid of parentheses

8v-8v+4+20=0

We add all the numbers together, and all the variables

24!=0

There is no solution for this equation

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