10(t-2)+4t=7(2t+2)-11

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Solution for 10(t-2)+4t=7(2t+2)-11 equation:


Simplifying
10(t + -2) + 4t = 7(2t + 2) + -11

Reorder the terms:
10(-2 + t) + 4t = 7(2t + 2) + -11
(-2 * 10 + t * 10) + 4t = 7(2t + 2) + -11
(-20 + 10t) + 4t = 7(2t + 2) + -11

Combine like terms: 10t + 4t = 14t
-20 + 14t = 7(2t + 2) + -11

Reorder the terms:
-20 + 14t = 7(2 + 2t) + -11
-20 + 14t = (2 * 7 + 2t * 7) + -11
-20 + 14t = (14 + 14t) + -11

Reorder the terms:
-20 + 14t = 14 + -11 + 14t

Combine like terms: 14 + -11 = 3
-20 + 14t = 3 + 14t

Add '-14t' to each side of the equation.
-20 + 14t + -14t = 3 + 14t + -14t

Combine like terms: 14t + -14t = 0
-20 + 0 = 3 + 14t + -14t
-20 = 3 + 14t + -14t

Combine like terms: 14t + -14t = 0
-20 = 3 + 0
-20 = 3

Solving
-20 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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