10(q-2)+8=4(q+2)-2

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Solution for 10(q-2)+8=4(q+2)-2 equation: 



10(q-2)+8=4(q+2)-2

We move all terms to the left:

10(q-2)+8-(4(q+2)-2)=0

We multiply parentheses

10q-(4(q+2)-2)-20+8=0



We calculate terms in parentheses: -(4(q+2)-2), so:

4(q+2)-2

We multiply parentheses

4q+8-2

We add all the numbers together, and all the variables

4q+6

Back to the equation:

-(4q+6)



We add all the numbers together, and all the variables

10q-(4q+6)-12=0

We get rid of parentheses

10q-4q-6-12=0

We add all the numbers together, and all the variables

6q-18=0

We move all terms containing q to the left, all other terms to the right

6q=18

q=18/6

q=3

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