10(n+4)=2(n+40)

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Solution for 10(n+4)=2(n+40) equation:


Simplifying
10(n + 4) = 2(n + 40)

Reorder the terms:
10(4 + n) = 2(n + 40)
(4 * 10 + n * 10) = 2(n + 40)
(40 + 10n) = 2(n + 40)

Reorder the terms:
40 + 10n = 2(40 + n)
40 + 10n = (40 * 2 + n * 2)
40 + 10n = (80 + 2n)

Solving
40 + 10n = 80 + 2n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2n' to each side of the equation.
40 + 10n + -2n = 80 + 2n + -2n

Combine like terms: 10n + -2n = 8n
40 + 8n = 80 + 2n + -2n

Combine like terms: 2n + -2n = 0
40 + 8n = 80 + 0
40 + 8n = 80

Add '-40' to each side of the equation.
40 + -40 + 8n = 80 + -40

Combine like terms: 40 + -40 = 0
0 + 8n = 80 + -40
8n = 80 + -40

Combine like terms: 80 + -40 = 40
8n = 40

Divide each side by '8'.
n = 5

Simplifying
n = 5

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