10(n+3)=1/2(24-14n)

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Solution for 10(n+3)=1/2(24-14n) equation: 



10(n+3)=1/2(24-14n)

We move all terms to the left:

10(n+3)-(1/2(24-14n))=0



Domain of the equation: 2(24-14n))!=0

n∈R



We add all the numbers together, and all the variables

10(n+3)-(1/2(-14n+24))=0

We multiply parentheses

10n-(1/2(-14n+24))+30=0

We multiply all the terms by the denominator


10n*2(-14n+24))-(1+30*2(-14n+24))=0

Wy multiply elements

20n^2(-+60n(-=0

We use the square of the difference formula

20n^2(-60n(-=0

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