10(b-3)+3=-(-3b-8)

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Solution for 10(b-3)+3=-(-3b-8) equation: 



10(b-3)+3=-(-3b-8)

We move all terms to the left:

10(b-3)+3-(-(-3b-8))=0

We multiply parentheses

10b-(-(-3b-8))-30+3=0



We calculate terms in parentheses: -(-(-3b-8)), so:

-(-3b-8)

We get rid of parentheses

3b+8

Back to the equation:

-(3b+8)



We add all the numbers together, and all the variables

10b-(3b+8)-27=0

We get rid of parentheses

10b-3b-8-27=0

We add all the numbers together, and all the variables

7b-35=0

We move all terms containing b to the left, all other terms to the right

7b=35

b=35/7

b=5

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