10(b-12)=4(4b-9)

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Solution for 10(b-12)=4(4b-9) equation: 



10(b-12)=4(4b-9)

We move all terms to the left:

10(b-12)-(4(4b-9))=0

We multiply parentheses

10b-(4(4b-9))-120=0



We calculate terms in parentheses: -(4(4b-9)), so:

4(4b-9)

We multiply parentheses

16b-36

Back to the equation:

-(16b-36)



We get rid of parentheses

10b-16b+36-120=0

We add all the numbers together, and all the variables

-6b-84=0

We move all terms containing b to the left, all other terms to the right

-6b=84

b=84/-6

b=-14

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