10(a+1)-14a=9-(4a-1)

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Solution for 10(a+1)-14a=9-(4a-1) equation:


Simplifying
10(a + 1) + -14a = 9 + -1(4a + -1)

Reorder the terms:
10(1 + a) + -14a = 9 + -1(4a + -1)
(1 * 10 + a * 10) + -14a = 9 + -1(4a + -1)
(10 + 10a) + -14a = 9 + -1(4a + -1)

Combine like terms: 10a + -14a = -4a
10 + -4a = 9 + -1(4a + -1)

Reorder the terms:
10 + -4a = 9 + -1(-1 + 4a)
10 + -4a = 9 + (-1 * -1 + 4a * -1)
10 + -4a = 9 + (1 + -4a)

Combine like terms: 9 + 1 = 10
10 + -4a = 10 + -4a

Add '-10' to each side of the equation.
10 + -10 + -4a = 10 + -10 + -4a

Combine like terms: 10 + -10 = 0
0 + -4a = 10 + -10 + -4a
-4a = 10 + -10 + -4a

Combine like terms: 10 + -10 = 0
-4a = 0 + -4a
-4a = -4a

Add '4a' to each side of the equation.
-4a + 4a = -4a + 4a

Combine like terms: -4a + 4a = 0
0 = -4a + 4a

Combine like terms: -4a + 4a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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