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10(7y-2-3)=(2+6y-4)
We move all terms to the left:
10(7y-2-3)-((2+6y-4))=0
We add all the numbers together, and all the variables
10(7y-5)-((6y-2))=0
We multiply parentheses
70y-((6y-2))-50=0
We calculate terms in parentheses: -((6y-2)), so:We get rid of parentheses
(6y-2)
We get rid of parentheses
6y-2
Back to the equation:
-(6y-2)
70y-6y+2-50=0
We add all the numbers together, and all the variables
64y-48=0
We move all terms containing y to the left, all other terms to the right
64y=48
y=48/64
y=3/4
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